Posted on: 01:27 Tue, 19 Jun 2018





WELCOME TO JFT JUPEB 2018 MATHEMATICS ANSWERS
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EXAM TIME:-
Wednesday 20th June 2018
- 9:-00am-12:-00pm
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MATHS OBJ:-
1-10: CACBBABCCB
11-20: D*DCBAACAA
21-30: CADDBBACAB
31-40: AA-BDCBDBAD
41-50: CBC-B do d rest pls
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MATHS ESSAY ANSWER:-

(1)

[ 1+3/1+i]²

[1 + I +3/ 1 + I]²

[4 + I/ 1+I]²
Rationalise the denominator

[ ( 4 + I) ( 1 - I)/ (1+I)(1-i)]²

[ 4-4i + i - i²/ 1 - i²]²

1² = -1

[ 4-3i -(-I)/ 1 -(-1)]²

[ 4-3i + i/1 + I ]²

[ 5 - 3i/2 ]

=5² - 2 (5)(3i) + (3i)²/2²
= 25 - 30i +9i²/4

1² =-1

= 25 - 30i - 9/4

= 16 - 30i/4

=2(8 - 15i)/4

=8 - 15i/2

=4 - 15i/2

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(2c) x² + y² - 4x +6y - 12=0

x² + y² - 2gx - 2fy + C=0

-2g² =-4

g=2

-2fy=by

F= 6/-2
= -3

C= -12

g² + f² - x² = C

r=√g² + f² - C

r=√2² + f-3² - 12

r= 5

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