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Neco 2018 Physics Practical Answers – June/July Expo
Views: 2265  |  Comments: 2 |  Posted: 12:39 Mon, 04 Jun 2018
Photo Kunlessi (¥ 15734 NU)
Star:Ultimate ult
Created Topics: 1540
Replies: 110
Posted on: 12:39 Mon, 04 Jun 2018




+++++++++++++++++++++++++++++++++++
Exam Time: Tuesday 5th June 2018
Practical – Physics – 10: 00am – 12: 45pm++++++++++++++++++++++++++++++++++


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ALWAYS SUBSCRIBE IF YOU WANT YOUR ANSWERS BEFORE THE EXAM
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PHYSICS PRACTICAL ANSWER:-


(2a)
In a tabular form:

Under tita°:
75, 65, 55, 45, 35

Under MO(cm):
1.1, 2.0, 2.5, 3.4, 3.9

Under NO(cm):
6.2, 6.4, 6.6, 6.8, 7.2

Under H=MO/NO:
0.177, 0.313, 0.379, 0.500, .542

Under Costita:
0.2588, 0.4226, 0.5736, 0.7071, 0.8192

(2axiii)
From the graph
Slope, S =Δcostita/^ΔH
= 0.75-0.45/0.5-0.3
= 0.3/0.2
=1.5

(2axiv)
(i) I ensured both the object and the pins were in straight lines so as to avoid error due to parallax.
(ii) I made sure there was no air interference

(2bi)
Snell's law of refraction states that the ratio of the sine of angle of incidence to the sine of the angle of refraction is a constant for a given pair of media.
I.e Sini/sinr = Π
Where Π is known as refractive index.

(2bii)
Given refractive index of glass = 1.5
i.e aΠg = 1.5(from air to glass)
SinC/sin90 = gΠa
SinC/Sinn90 = 1/aΠg
SinC/1 = 1/1.5
SinC= 0.6667
C = sin^-1(0.6667)
Critical angle for glass C = 42°


====================================================


(3a)
(ii) Vo = 2.00v

(3av)
In a tabular form
Under S/N
1, 2, 3, 4, 5

Under R(ohms):
2, 3, 4, 5, 6

Under V(v):
2.10, 2.30, 2.40, 2.50, 2.60

Under R^-1:
0.500, 0.333, 0.250, 0.200, 0.167

Under V^-1(v^-1):
0.476, 0.435, 0.417, 0.400, 0.385

3vii Slope, = Δv^-1/ΔR-1
= 0.5 - 0.355/0.6 - 0
= 0.145/0.6
S = 0.242

Intercept, C = 0.355v^-1

(3aviii)
K = S/C
K = 0.242/0.355
K = 0.68

(3ix)
(i) I ensured tight connections.
(ii) I ensured clean terminals.

(3bi)
(i) Temperature of wire
(ii) Cross sectional area of wire
(iii) Length of wire
(iv) Nature of wire

(3bii)
Draw the diagram

Effective E.m.f = 2v(parallel connection)
Effective internal resistance
= r * r/r + r = r/2ohms

Current, I , 0.8A
External resistance R = 2A
Using,
E = I(R+r)
2 = 0.8(2+r/2)
2.5 = (2+r/2)
2.5 - 2 = r/2
0.5 = r/2
r = 0.5*2 = 1ohms

Completed

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Replies

Photo Emmanuel Yohanna (¥ 3 NU)
Star: Novice
Created Topics: 0
Replies: 1
Posted on: 12:39 Mon, 04 Jun 2018
Is like u syd registered user get answers free, bt i dnt know y is like dis now tnks
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Photo Kunlessi (¥ 15734 NU)
Star: Ultimate ult
Created Topics: 1540
Replies: 110
Posted on: 12:39 Mon, 04 Jun 2018
No free Answer here u subscribe and get it on time
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